Aperture (antenna)

In electromagnetics and antenna theory, the aperture of an antenna is defined as "A surface, near or on an antenna, on which it is convenient to make assumptions regarding the field values for the purpose of computing fields at external points. The aperture is often taken as that portion of a plane surface near the antenna, perpendicular to the direction of maximum radiation, through which the major part of the radiation passes."^[1]

The effective area of an antenna is defined as "In a given direction, the ratio of the available power at the terminals of a receiving antenna to the power flux density of a plane wave incident on the antenna from that direction, the wave being polarization matched to the antenna."^[1] Of particular note in this definition is that both effective area and power flux density are functions of incident angle of a plane wave. Assume a plane wave from a particular direction ${\displaystyle (\theta ,\phi )}$, which are the azimuth and elevation angles relative to the array normal, has a power flux density${\displaystyle \|{\vec {S}}\|}$; this is the amount of power passing through a unit area normal to the direction of the plane wave of one square meter.

By definition, if an antenna delivers ${\displaystyle P_{\text{O}}}$watts to the transmission line connected to its output terminals when irradiated by a uniform field of power density ${\displaystyle |S(\theta ,\phi )|}$ watts per square meter, the antenna's effective area ${\displaystyle A_{\text{e}}}$ for the direction of that plane wave is given by

${\displaystyle A_{\text{e}}(\theta ,\phi )={\frac {P_{O}}{\|{\vec {S}}(\theta ,\phi )\|}}.}$

The power ${\displaystyle P_{\text{O}}}$ accepted by the antenna (the power at the antenna terminals) is less than the power ${\displaystyle P_{\text{R}}}$ received by an antenna by the radiation efficiency${\displaystyle \eta }$ of the antenna.^[1]${\displaystyle P_{\text{R}}}$ is equal to the power density of the electromagnetic energy ${\displaystyle |S(\theta ,\phi )|=|{\vec {S}}\cdot {\hat {a}}|}$, where ${\displaystyle {\hat {a}}}$ is the unit vector normal to the array aperture, multiplied by the physical aperture area ${\displaystyle A}$. The incoming radiation is assumed to have the same polarization as the antenna. Therefore,

${\displaystyle P_{\text{O}}=\eta P_{\text{R}}=\eta A|{\vec {S}}\cdot {\hat {a}}|=\eta A\|{\vec {S}}(\theta ,\phi )\|\cos \theta \cos \phi ,}$

and

${\displaystyle A_{\text{e}}(\theta ,\phi )=\eta A\cos \theta \cos \phi .}$

The effective area of an antenna or aperture is based upon a receiving antenna. However, due to reciprocity, an antenna's directivity in receiving and transmitting are identical, so the power transmitted by an antenna in different directions (the radiation pattern) is also proportional to the effective area ${\displaystyle A_{e}}$. When no direction is specified, ${\displaystyle A_{e}}$ is understood to refer to its maximal value.^[1]

In general, the aperture of an antenna cannot be directly inferred from its physical size.^[4] However so-called aperture antennas such as parabolic dishes and horn antennas, have a large (relative to the wavelength) physical area ${\displaystyle A_{\text{phys}}}$ which is opaque to such radiation, essentially casting a shadow from a plane wave and thus removing an amount of power ${\displaystyle A_{\text{phys}}S}$ from the original beam. That power removed from the plane wave can be actually received by the antenna (converted into electrical power), reflected or otherwise scattered, or absorbed (converted to heat). In this case the effective aperture${\displaystyle A_{e}}$ is always less than (or equal to) the area of the antenna's physical aperture ${\displaystyle A_{\text{phys}}}$, as it accounts only for the portion of that wave actually received as electrical power. An aperture antenna's aperture efficiency${\displaystyle e_{\text{a}}}$ is defined as the ratio of these two areas:

${\displaystyle e_{\text{a}}={\frac {A_{e}}{A_{\text{phys}}}}.}$

The aperture efficiency is a dimensionless parameter between 0 and 1 that measures how close the antenna comes to using all the radio wave power intersecting its physical aperture. If the aperture efficiency were 100%, then all the wave's power falling on its physical aperture would be converted to electrical power delivered to the load attached to its output terminals, so these two areas would be equal: ${\displaystyle A_{\text{e}}=A_{\text{phys}}}$. But due to nonuniform illumination by a parabolic dish's feed, as well as other scattering or loss mechanisms, this is not achieved in practice. Since a parabolic antenna's cost and wind load increase with the physical aperture size, there may be a strong motivation to reduce these (while achieving a specified antenna gain) by maximizing the aperture efficiency. Aperture efficiencies of typical aperture antennas vary from 0.35 to well over 0.70.

Note that when one simply speaks of an antenna's "efficiency", what is most often meant is the radiation efficiency, a measure which applies to all antennas (not just aperture antennas) and accounts only for the gain reduction due to losses. Outside of aperture antennas, most antennas consist of thin wires or rods with a small physical cross-sectional area (generally much smaller than ${\displaystyle A_{\text{e}}}$) for which "aperture efficiency" is not even defined.^[5]

The directivity of an antenna, its ability to direct radio waves preferentially in one direction or receive preferentially from a given direction, is expressed by a parameter ${\displaystyle G}$ called antenna gain. This is most commonly defined as the ratio of the power ${\displaystyle P_{\text{o}}}$ received by that antenna from waves in a given direction to the power ${\displaystyle P_{\text{iso}}}$ that would be received by an ideal isotropic antenna, that is, a hypothetical antenna that receives power equally well from all directions.^{[Note 1]} It can be seen that (for antennas at a given frequency) gain is also equal to the ratio of the apertures of these antennas:^[6]

${\displaystyle G={\frac {P_{\text{o}}}{P_{\text{iso}}}}={\frac {A_{\text{e}}}{A_{\text{iso}}}}.}$

As shown below, the aperture of a lossless isotropic antenna, which by this definition has unity gain, is

${\displaystyle A_{\text{iso}}={\frac {\lambda ^{2}}{4\pi }},}$

where ${\displaystyle \lambda }$ is the wavelength of the radio waves. Thus

${\displaystyle G={\frac {A_{\text{e}}}{A_{\text{iso}}}}={\frac {4\pi A_{\text{e}}}{\lambda ^{2}}}.}$

So antennas with large effective apertures are considered high-gain antennas (or beam antennas), which have relatively small angular beam widths. As receiving antennas, they are much more sensitive to radio waves coming from a preferred direction compared to waves coming from other directions (which would be considered interference). As transmitting antennas, most of their power is radiated in a particular direction at the expense of other directions. Although antenna gain and effective aperture are functions of direction, when no direction is specified, these are understood to refer to their maximal values, that is, in the direction(s) of the antenna's intended use (also referred to as the antenna's main lobe or boresight).

The fraction of the power delivered to a transmitting antenna that is received by a receiving antenna is proportional to the product of the apertures of both the antennas and inversely proportional to the squared values of the distance between the antennas and the wavelength. This is given by a form of the Friis transmission formula:^[7]

${\displaystyle {\frac {P_{\text{r}}}{P_{\text{t}}}}={\frac {A_{\text{r}}A_{\text{t}}}{d^{2}\lambda ^{2}}},}$

where

${\displaystyle P_{\text{t}}}$ is the power fed into the transmitting antenna input terminals,

${\displaystyle P_{\text{r}}}$ is the power available at receiving antenna output terminals,

${\displaystyle A_{\text{r}}}$ is the effective area of the receiving antenna,

${\displaystyle A_{\text{t}}}$ is the effective area of the transmitting antenna,

${\displaystyle d}$ is the distance between antennas (the formula is only valid for ${\displaystyle d}$ large enough to ensure a plane wave front at the receive antenna, sufficiently approximated by ${\displaystyle d\gtrsim 2a^{2}/\lambda }$, where ${\displaystyle a}$ is the largest linear dimension of either of the antennas),

${\displaystyle \lambda }$ is the wavelength of the radio frequency.

The aperture of an isotropic antenna, the basis of the definition of gain above, can be derived on the basis of consistency with thermodynamics.^[8][9][10] Suppose that an ideal isotropic antenna A with a driving-point impedance of R sits within a closed system CA in thermodynamic equilibrium at temperature T. We connect the antenna terminals to a resistor also of resistance R inside a second closed system CR, also at temperature T. In between may be inserted an arbitrary lossless electronic filter F_ν passing only some frequency components.

Each cavity is in thermal equilibrium and thus filled with black-body radiation due to temperature T. The resistor, due to that temperature, will generate Johnson–Nyquist noise with an open-circuit voltage whose mean-squared spectral density is given by

${\displaystyle {\overline {v_{n}^{2}}}=4k_{\text{B}}TR\,\eta (f),}$

where ${\displaystyle \eta (f)}$ is a quantum-mechanical factor applying to frequency f; at normal temperatures and electronic frequencies ${\displaystyle \eta (f)=1}$, but in general is given by

${\displaystyle \eta (f)={\frac {hf/k_{\text{B}}T}{e^{hf/k_{\text{B}}T}-1}}.}$

The amount of power supplied by an electrical source of impedance R into a matched load (that is, something with an impedance of R, such as the antenna in CA) whose rms open-circuit voltage is v_rms is given by

${\displaystyle P={\frac {{\text{v}}_{\text{rms}}^{2}}{4{\text{R}}}}.}$

The mean-squared voltage ${\displaystyle {\overline {v_{n}^{2}}}={\text{v}}_{\text{rms}}^{2}}$ can be found by integrating the above equation for the spectral density of mean-squared noise voltage over frequencies passed by the filter F_ν. For simplicity, let us just consider F_ν as a narrowband filter of bandwidth B₁ around central frequency f₁, in which case that integral simplifies as follows:

${\displaystyle P_{R}={\frac {\int _{0}^{\infty }4k_{\text{B}}TR\,\eta (f)\,F_{\nu }(f)\,df}{4{\text{R}}}}}$

${\displaystyle \qquad ={\frac {4k_{\text{B}}TR\,\eta (f_{1})\,B_{1}}{4{\text{R}}}}=k_{\text{B}}T\,\eta (f_{1})\,B_{1}.}$

This power due to Johnson noise from the resistor is received by the antenna, which radiates it into the closed system CA.

The same antenna, being bathed in black-body radiation of temperature T, receives a spectral radiance (power per unit area per unit frequency per unit solid angle) given by Planck's law:

${\displaystyle {\text{P}}_{f,A,\Omega }(f)={\frac {2hf^{3}}{c^{2}}}{\frac {1}{e^{hf/k_{\text{B}}T}-1}}={\frac {2f^{2}}{c^{2}}}\,k_{\text{B}}T\,\eta (f),}$

using the notation ${\displaystyle \eta (f)}$ defined above.

However, that radiation is unpolarized, whereas the antenna is only sensitive to one polarization, reducing it by a factor of 2. To find the total power from black-body radiation accepted by the antenna, we must integrate that quantity times the assumed cross-sectional area A_eff of the antenna over all solid angles Ω and over all frequencies f:

${\displaystyle P_{A}=\int _{0}^{\infty }\int _{4\pi }\,{\frac {P_{f,A,\Omega }(f)}{2}}A_{\text{eff}}(\Omega ,f)\,F_{\nu }(f)\,d\Omega \,df.}$

Since we have assumed an isotropic radiator, A_eff is independent of angle, so the integration over solid angles is trivial, introducing a factor of 4π. And again we can take the simple case of a narrowband electronic filter function F_ν which only passes power of bandwidth B₁ around frequency f₁. The double integral then simplifies to

${\displaystyle P_{A}=2\pi P_{f,A,\Omega }(f)A_{\text{eff}}\,B_{1}={\frac {4\pi \,k_{\text{B}}T\,\eta (f_{1})}{\lambda _{1}^{2}}}A_{\text{eff}}B_{1},}$

where ${\displaystyle \lambda _{1}=c/f_{1}}$ is the free-space wavelength corresponding to the frequency f₁.

Since each system is in thermodynamic equilibrium at the same temperature, we expect no net transfer of power between the cavities. Otherwise one cavity would heat up and the other would cool down in violation of the second law of thermodynamics. Therefore, the power flows in both directions must be equal:

${\displaystyle P_{A}=P_{R}.}$

We can then solve for A_eff, the cross-sectional area intercepted by the isotropic antenna:

${\displaystyle {\frac {4\pi \,k_{\text{B}}T\,\eta (f_{1})}{\lambda _{1}^{2}}}A_{\text{eff}}B_{1}=k_{\text{B}}T\,\eta (f_{1})\,B_{1},}$

${\displaystyle A_{\text{eff}}={\frac {\lambda _{1}^{2}}{4\pi }}.}$

We thus find that for a hypothetical isotropic antenna, thermodynamics demands that the effective cross-section of the receiving antenna to have an area of λ²/4π. This result could be further generalized if we allow the integral over frequency to be more general. Then we find that A_eff for the same antenna must vary with frequency according to that same formula, using λ = c/f. Moreover, the integral over solid angle can be generalized for an antenna that is not isotropic (that is, any real antenna). Since the angle of arriving electromagnetic radiation only enters into A_eff in the above integral, we arrive at the simple but powerful result that the average of the effective cross-section A_eff over all angles at wavelength λ must also be given by

Although the above is sufficient proof, we can note that the condition of the antenna's impedance being R, the same as the resistor, can also be relaxed. In principle, any antenna impedance (that isn't totally reactive) can be impedance-matched to the resistor R by inserting a suitable (lossless) matching network. Since that network is lossless, the powers P_A and P_R will still flow in opposite directions, even though the voltage and currents seen at the antenna and resistor's terminals will differ. The spectral density of the power flow in either direction will still be given by ${\displaystyle k_{\text{B}}T\,\eta (f)}$, and in fact this is the very thermal-noise power spectral density associated with one electromagnetic mode, be it in free-space or transmitted electrically. Since there is only a single connection to the resistor, the resistor itself represents a single mode. And an antenna, also having a single electrical connection, couples to one mode of the electromagnetic field according to its average effective cross-section of ${\displaystyle \lambda _{1}^{2}/(4\pi )}$.

• Surface equivalence principle